Refactoring if's, what's the mistake?

• 0
  How to put type = "radio" state in if as checked?
  Previously, it worked like this for me:
  

  if (document.getElementById('radiobutton').checked) {
  		user_choice = "EAGLE";
  		console.log(user_choice);
  		return;
  	}
  	if (document.getElementById('radiobutton2').checked) {
  		user_choice = "TAILS";
  		console.log(user_choice);
  		return;
  	} else {
  		user_choice = null;

  
  
  Now I want to fix it with a construction of the form
  

  const user_choice = document.getElementById('radiobutton').checked=true ? user_choice = "EAGLE" : user_choice = "TAILS";

  JavaScript Anonymous, Mar 10, 2020

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1 Answers
• 0

  const user_choice = document.getElementById('radiobutton').checked ?  "EAGLE" :  "TAILS";

  Anonymous

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