Refactoring if's, what's the mistake?

  • 0
    How to put type = "radio" state in if as checked?
    Previously, it worked like this for me:
    if (document.getElementById('radiobutton').checked) {
    		user_choice = "EAGLE";
    		console.log(user_choice);
    		return;
    	}
    	if (document.getElementById('radiobutton2').checked) {
    		user_choice = "TAILS";
    		console.log(user_choice);
    		return;
    	} else {
    		user_choice = null;


    Now I want to fix it with a construction of the form
    const user_choice = document.getElementById('radiobutton').checked=true ? user_choice = "EAGLE" : user_choice = "TAILS";
    JavaScript Anonymous, Mar 10, 2020

  • 1 Answers
  • 0
    const user_choice = document.getElementById('radiobutton').checked ?  "EAGLE" :  "TAILS";
    Anonymous

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