Return does not return a value, why?

• 0
  Hello, I just started learning JS, so I don’t know some points. Here is a part of the code, my functions do not pass values ​​back, but everything works. That is, I have a logic problem. They said to fix it using reassignment or alert, but nothing came of it. I also found nothing in the internet. Can someone explain what I did wrong and how to fix it? (
  

  switch(operacia) {
  	  case "!" : {sorting (num1,num2, res2)
  	           alert (res2);} break;
  	
  	case "?" : { inverting (num1,num2, res2)
  	           alert (res2);} break;
  	default: { alert ('C такой операцией мы не работаем'); } break;
  										} 
  function sorting (num1,num2) {
  	var arr = num1.split(",");
  	var arr2 = num2.split(",");
  	var arr3 = arr.concat(arr2);
  	 res2 = arr3.sort();
  	return res2;
  }
  
  function inverting (num1,num2) {
  	var arr = num1.split(",");
  	var arr2 = num2.split(",");
  	var arr3 = arr.concat(arr2);
  	 res2 = arr3.reverse();
  	return res2;
  }

  JavaScript Anonymous, May 21, 2019

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2 Answers
• 0
  return works, you just need to assign the result somewhere. : thinking
  
  

  const result = sorting (num1,num2);
  
  alert (result);

  Anonymous

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• 0
  function sorting has two arguments and is called with three. You can't do that.

  Anonymous

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