C ++ inference operator overloading?

• 0
  There is a class:
  
  

  using namespace std;
  
  class Stroka
  {
      protected:
          static int iCount;
          char * p_char;
          int  size;
      public:
          Stroka()
          {
              cout << "КОНСТРУКТОР  БЕЗ  ПАРАМЕТРОВ [Базовый]" << endl;
              size = 1;
              p_char = new char[size];
              *p_char = '\0';
          }
  
          Stroka(const char *st)
          {
              cout << "КОНСТРУКТОР  С  ПАРАМЕТРАМИ [Базовый]" << endl;
              size = strlen(st);
              p_char = new char[size];
              strcpy(p_char, st);
          }
  
          Stroka(const char ch)
          {
              cout << "КОНСТРУКТОР  С  ПАРАМЕТРАМИ КОТОРЫЙ ПРИНИМАЕТ СИМВОЛ [Базовый]" << endl;
              size = 2;
              p_char = new char[size];
              p_char[0] =  ch;
              p_char[1] = '\0';
          }
  
          Stroka(const Stroka &st)
          {
              iCount++;
              cout << "КОНСТРУКТОР КОПИРОВАНИЯ [Базовый] ВЫЗЫВАЛСЯ " << iCount << " РАЗ" << endl;
              size = strlen(st.p_char);
              p_char = new char[size];
              strcpy(p_char, st.p_char);
  
          }
  
          Stroka operator=(const Stroka & str)
          {
              cout << "ПЕРЕГРУЗКА ОПЕРАЦИИ = [Базовый]" << endl;
              delete [] p_char;
  
              p_char = new char[str.size];
              size = str.size;
  
              strcpy(p_char, str.p_char);
  
              return * this;
          }
  
          unsigned int Size()
          {
              return size;
          }
  
          ~Stroka()
          {
              cout << "ДЕСТРУКТОР [Базовый]" << endl;
              delete [] p_char;
          }
  
          friend ostream & operator<<(ostream &of ,const Stroka & obj);
  };
  
  ostream & operator<<(ostream &of ,const Stroka & obj)
  {
      of << obj.p_char << endl;
  
      return of;
  }

  
  
  I can't understand why, when using cout, it does not display the corresponding line, but only the address. Maybe he’s clever somewhere?

  C++ Gabriel Heath, Sep 17, 2019

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0 Answers