How to make sure that after validation of the form - at the click of a button, if everything is good, then transfer to the page with confirmation?

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    Hello, I made it so that when you click on the button, a popup opens. It contains a form (screen below). Question: how to make sure that on JS, after successful validation, clicking on the "Order a call" button closes this popup and opens the second one with a confirmation about ordering a call?

    JavaScript Anonymous, Nov 20, 2019

  • 1 Answers
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    Where ajax is performed, just push the fadeout method to the first modal and fadeIn the second, if you use jquery, if there is enough native class with a display block and that's all, if you use to send axios, put the idea that I described above to you in .then

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